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(B) The reaction is a Hofmann elimination. Due to the presence of a bulky and poor leaving group,$-\overset{\oplus }{N}Me_3$,the base $(OH^-)$ abstrac

Vedclass · Accepted Answer

methylenecyclohexane

Vedclass · Answer

(B) The reaction is a Hofmann elimination. Due to the presence of a bulky and poor leaving group,$-\overset{\oplus }{N}Me_3$,the base $(OH^-)$ abstracts a proton from the less hindered $\beta$-carbon to form the less substituted alkene as the major product. This proceeds through a transition state with carbanion-like character. Thus,the major product is methylenecyclohexane.

The major product $A$ is:

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